Which of the following assignment statements are syntactically correct?
PHP
i. $a = -10;
ii. 10 = $b;
iii. $a_b = $a_b + 1;
iv. $a = "COWS"; |
v. $a = COWS;
vi. $a + $b = 40;
vii. $a = 3 $b;
viii. $a = "true"; |
ix. $a = true;
x. $a %= 2;
xi. $a += 1;
xii. $a =* 2; |
Java, C++, C#
i. a = -10;
ii. 10 = b;
iii. a_b = a_b + 1;
iv. a = "COWS"; |
v. a = COWS;
vi. a + b = 40;
vii. a = 3 b;
viii. a = "true"; |
ix. a = true;
x. a %= 2;
xi. a += 1;
xii. a =* 2; |
Visual Basic, Python
i. a = -10
ii. 10 = b
iii. a_b = a_b + 1
iv. a = "COWS" |
v. a = COWS
vi. a + b = 40
vii. a = 3 b
viii. a = "true" |
ix. a = true
x. a -= b
xi. a += 1
xii. a =* 2 |
Solution
- Correct. It assigns the integer value -10 to variable
a.
- Wrong. On the left side of the assignment operator, only one variable can exist.
- Correct. It increases variable
a_b by one.
- Correct. It assigns the string (the text) COWS to variable
a.
- Correct. It assigns the content of constant COWS to variable
a.
- Wrong. On the left side of the assignment operator, only one variable can exist.
- Wrong. It should have been written as
a = 3 * b (as $a = 3 * $b in PHP).
- Correct. It assigns the string true to variable
a.
- Correct. It assigns the value
true to variable a.
- Correct. This is equivalent to
a = a - b (to $a = $a - $b in PHP).
- Correct. This is equivalent to
a = a + 1 (to $a = $a + 1 in PHP).
- Wrong. It should have been written as
a *= 2 (as $a *= 2 in PHP)